Question

8. Find the largest number which divides 438 and 606, leaving remainder
6 in each case
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Answer 1

Answer:

Given that the largest number which divides 438 and 606 leaving remainder 6.

We need to deduct the remainder 6 from both the cases.

438 - 6 = 432

606 - 6 = 600.

Therefore HCF of 432 and 600 gives us the largest number remainder that gives remainder 6.

Prime factorization of 432 = 2 * 2 * 2 * 2 * 3 * 3 * 

Prime factorization of 600 = 2 * 2 * 2 * 3 * 5 * 5

HCF(432,600) = 2 * 2 * 2 * 3

                         = 24.

Hence the largest number is 24 that divides 438 and 600 leaving remainder 6.

Answer 2

Answer:

24

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