Question

8. Find the least number of six digits which
on dividing by 6, 12, 18 and 24 leaves a
remainder of 5 in each case.







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Answer 1

Answer:

6=2×3

12=2×3×2

18=2×3×3

24=2×3×2×2

LCM of 6,12,18 and 24=2×2×2×3×3=72

Therefore, the required number=72+5=77