Question

8. Find the least number which when divided by 30, 36, 54 and 63 leaves 8 as remaine
in each case.
9. Find the largest number of four-digits which when divided by 9,12, 24 and 45 leave
a remainder 5 in each case.
10. Find the least number of five-digits​

Answer 1

STEP 1:

LCM OF DIVISORS

LCM OF( 9,12,24,45) IS 360

STEP 2:

We know the largest five digit number is 99999

Now to find the largest five digit number which satisfy the given conditons then do the following

A) 360*N-6

N, is the quotient of 99999/360

U will get the answer as 360*277–6= 97214

B) Divide 99999/360

U will get remainder as 279

SUBTRACT 279 FROM 99999 WHICH IS 99720

Now 99720–6= 97214 which will be ur answer