Math, asked by sahanikanchan108, 5 months ago

8. Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each
case.

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Answers

Answered by satyamkumar5428

0

Answer:

95

Step-by-step explanation:

L.C.M. of 6,15,18 = 90

When 90 is divided by 6,15,18 then no remainder is left . So, required number = (90+5) = 95

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