Question

8. Find the least number which when
divided by 60, 120 and 180 leaves a
remainder 5 in each case.​

Answer 1

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To find that least numberw hich divide by 60, 120and 180 leave a reminder 5.

In ,case we have to find the l.c.m of the given numbers

and then add five in that number

$\therefore \: lcm \: of \:60 \: 120 \: and180 \: is$

60 = 2×2×3×5

120 =2×2×2×3×5

180 =2×2×3×3×5

l.c.m =360

Now, add 5

so, 5 + 360 = 365

Hence, 365 is the least number which is divide by 60,120and 180 leaves reminder 5

• check ur answer :)
• Hope's it help u mate

Answer 2

Answer:

∴lcmof60120and180is

60 = 2×2×3×5

120 =2×2×2×3×5

180 =2×2×3×3×5

l.c.m =360

Now, add 5

so, 5 + 360 = 365

Hence, 365 is the least number which is divide by 60,120and 180 leaves reminder 5

chec