8. Find the lengths of the sides of the parallelogram. D 3x + 5 C 4x - 5 A 6x - IO B
Answers
Correct option is
Correct option isD
Correct option isDx=32, b=89 degrees, d=91 degrees
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore,
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘ x=5180−20=32
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘ x=5180−20=32 ∠B=2x+25=(2∗32)+25=89∘
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘ x=5180−20=32 ∠B=2x+25=(2∗32)+25=89∘ ∠D=3x−5=(3∗32)−5=91∘
Step-by-step explanation:
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Correct option is
Correct option isD
Correct option isDx=32, b=89 degrees, d=91 degrees
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore,
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘ x=5180−20=32
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘ x=5180−20=32 ∠B=2x+25=(2∗32)+25=89∘
Correct option isDx=32, b=89 degrees, d=91 degreesIn ∥gm opposite angles are supplementary.Therefore, ∠B+∠D=180∘ 2x+25+3x−5=180∘ x=5180−20=32 ∠B=2x+25=(2∗32)+25=89∘ ∠D=3x−5=(3∗32)−5=91∘
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