8. Find the number, which is smaller than 110000 but larger than 100000 and fully divisible by 8, 15 and 21.
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8 = 2*2*2
15 = 3*5
21 = 3*7
So LCM of (8, 15 , 21) = 2*2*2*3*5*7
= 840 ....
Multiples of LCM are also divisible by all these numbers.....
Now, 100000/840 = 119.04 (approx)
So, 840 * 119 is less than 100000.
So, 840 * 120 = 100800...
This is the only no. greater than 100000 and less than 110000 which is divisible by 8, 15, 21.
Feel free to ask any doubts
15 = 3*5
21 = 3*7
So LCM of (8, 15 , 21) = 2*2*2*3*5*7
= 840 ....
Multiples of LCM are also divisible by all these numbers.....
Now, 100000/840 = 119.04 (approx)
So, 840 * 119 is less than 100000.
So, 840 * 120 = 100800...
This is the only no. greater than 100000 and less than 110000 which is divisible by 8, 15, 21.
Feel free to ask any doubts
zeeshan0:
no your answer is wrong
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