Math, asked by zeeshan0, 1 year ago

8. Find the number, which is smaller than 110000 but larger than 100000 and fully divisible by 8, 15 and 21.

Answers

Answered by Anonymous
0
8 = 2*2*2
15 = 3*5
21 = 3*7

So LCM of (8, 15 , 21) = 2*2*2*3*5*7

= 840 ....

Multiples of LCM are also divisible by all these numbers.....

Now, 100000/840 = 119.04 (approx)

So, 840 * 119 is less than 100000.

So, 840 * 120 = 100800...

This is the only no. greater than 100000 and less than 110000 which is divisible by 8, 15, 21.



Feel free to ask any doubts




zeeshan0: no your answer is wrong
Anonymous: why ?
Anonymous: 100800 is divisible by 8, 15, 21
Anonymous: Also it is greater than 100000 and less than 110000
zeeshan0: answer is 109200
zeeshan0: try again
Anonymous: Actually, there are multiple such numbers....
Anonymous: 100800 is 1st such no.
Anonymous: Keep on adding 840 and you will get all other no.
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