8. Find the perimeter and area of a triangle whose sides are of lengths 52 cm, 56 cm
and 60 cm respectively.
Answers
Answered by
4
Answer: Perimeter = 168 cm; Area = 1344 cm²
Step-by-step explanation:
Perimeter = Sum of all sides = 52 cm + 56 cm + 60 cm = 168 cm
We can calculate area by using heron's formula.
Area =
s = semi perimeter = 168/2 = 84 cm
a = 52 cm
b = 56 cm
c = 60 cm
Area = 1344 cm²
Answered by
2
Step-by-step explanation:
the lengths are
- 52 cm (a)
- 56 cm (b)
- 60 cm (c)
so, the perimeter = (52+56+60) cm
= 168 cm
the half perimeter (s) = (168/2) = 84 cm.
now, the rule of the area of triangle
= √[s(s-a)(s-b)(s-c)]
so, the area = √[84(84-52)(84-56)(84-60)] cm²
= √[84×32×28×24] cm²
= √1806336 cm²
= 1,344 cm²
I hope it is a helpful answer .........
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