Question

8. Find the quadratic polynomial root3/2, -root3/2
the zeroes.​

Answer 1

$x = \alpha = 3 \div 2 \\ x = \beta = - 3 \div 2 \\ s = \alpha + \beta = 0 \\ p = \alpha \beta = - 9 \div 2 \\ p(x) = x {}^{2} - sx + p \\ = x {}^{2} - 9 \div 2 \\ = 2x {}^{2} \div 2 - 9 \div 2 \\ answer \: ... = p(x) = 1 \div 2(2x {}^{2} - 9)$

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