Math, asked by amrendrajsr11, 7 months ago

8) Find the remainder on
dividing 2x^3-7x-1 I by (x+3) is
*​

Answers

Answered by Anonymous
0

Answer:

hope this helps u

Step-by-step explanation:

we can find remainder by this method

x+3=0

x= -3

p(x) = 2x³-7x-1

p(-3) = 2*[-3]³-7*-3-1

       = 2*-27+21-1

       = -54-1+21

      = -55+21

       = -34

remainder = -34

Answered by skasabsn
0

Answer:

28

Step-by-step explanation:

hope it helps you

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