Question

8. Find the smallest number of 5 digits which when divided by 20, 24, 35
and 45 leaves 5 as remainder.chapter is LCM AND GCF and answer is (10085)​

Answer 1

Answer:

Step-by-step explanation:

5-digit no.=LCM of 20 25 35 45=2520

Remainder=5

Required no.= 2520-5

=2515

Smallest 5 digit no.=10000

Now,10000÷2515 =31

Answer 2

Answer:

What you will give the answer

Step-by-step explanation:

that answer will be correct