8. Find the sum of 32 terms of an AP whose third term is 1 and the 6th term is
-11.
Answers
Answered by
5
Answer:
a+2d=1
a+5d=-11
4d=-12
d=-3 a= 7
s= 32/2(14+31*-3)
16(14-91)
= - (77*16)
= ans (solve)
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