8. Find the sum of the last 10 terms of the A.P. 8, 10, 12, ...., 126.
Answers
Answered by
2
Answer:
16, 18,20,22,24,26,28,30,32,34,36,38,40
Answered by
1
Answer:
1170
Step-by-step explanation:
from back
a= 126
d= -2
n=10
sn= (n/2)*(2a+(n-1)d)
s10 = 5*(2*126+9*(-2))
= 5*(252-18)
= 5*(234)
= 1170
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