Question

8.
Find the two parallel sides of a trapezium whose area is 1.6 m2, altitude is 10 dm
and one of the parallel sides is longer than the other by 8 dm.​

Answer 1

Answer:

12 dm and 20 dm

Step-by-step explanation:

$A_{trapezoid}$ = $\frac{b_{1} +b_{2} }{2}$ h

Let $b_{2}$ = $b_{1}$ + 8

$\frac{b_{1} +(b_{1} +8)}{2}$ × 10 = 160

$b_{1}$ + $b_{1}$ + 8 = 160 ÷ 5

2 $b_{1}$ = 32 - 8

$b_{1}$ = 12 dm = 1.2 m

$b_{2}$ = 12 + 8 = 20 dm = 2 m