Question

8
Find the value of
4 cot
T - sec I + sin I I
4
3​

Answer 1

Answer:  

3cosA=4sinA

tanA=  

4

3

​  

 

tanA=  

B

P

​  

=  

4

3

​  

 

Using Pythagoras Theorem,

H  

2

=P  

2

+B  

2

 

H  

2

=3  

2

+4  

2

 

H  

2

=5  

2

 

H=5

Now, 3−cot  

2

A+csc  

2

A = 3−(  

P

B

​  

)  

2

+(  

P

H

​  

)  

2

 

= 3−(  

3

4

​  

)  

2

+(  

3

5

​  

)  

2

 

= 3−  

9

16

​  

+  

9

25

​  

 

=  

9

27−16+25

​  

 

=  

9

36

​  

 

= 4

Step-by-step explanation: