Question

8. Find the value of each of the following polynomials
at the indicated values of variables :
4
(i) p(x) = 5x2 -
1 - 1
2' 2
5
(ii) p(x) = 3x3 + 2x - 3x2 + 4; x = 1/2,-1/2


(iii) p(y) = 5y2 + 4; y =-2/ √5 ,4√5
+
(iv) p(y) = 2y2 + 3π2; y = π, -2π​

Answer 1

Answer:

Step-by-step explanation:

1) p(1)= 5×2-3×1+7

= 10-3+7

=14  

Verify whether the values of x given in each case are the zeros of the polynomial or not.

1 P(x)=2x+1;x=-1/2

P(-1/2) = 2(-1/2) + 1 = -1 + 1 = 0   = 0

2) p(x)=5x-π;x=-3/2

P(-3/2) = 5(-3/2) - π = -15/2 - π  ≠ 0

3) p(x)=x²-1;x=+1

P(1) = 1² - 1 = 1 - 1  = 0  = 0

4) p(x)=(x-1)(x+2);x=-1,-2

P(-1) = (-1-1)(-1 + 2) = (-2)(1) = - 1 ≠ 0

P(-2) = (-2 -1)(-2 + 2) = (-3)(0) = 0 = 0

5) P(y)=y²;y=0

P(0) = 0² = 0 = 0

6) p(x)=ax+b;x=-b/a​

P(-b/a) = a(-b/a) + b = -b + b = 0 = 0

p(2)= 3×2×3-4×2+11

= 18-8+11

=21

in equation third where is t