Question

8. Find the value of k for which x = -2 is a root of the equation x/2 + x - 2 = kx - 1.
X
2
00​

Answer 1

Step-by-step explanation:

Heya!!

Here is your answer!!

Given: x= -2.

$x \div 2 + x - 2 = kx - 1$

$- 2 \div 2 + ( - 2) - 2 = k( - 2) - 1$

$- 1 - 4 = k( - 2)- 1$

$- 1 + 1 - 4 = - 2k$

$4 = 2k$

$k = 2.$

$hope \ it \ helps \ u$

Answer 2

Answer:

❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:

$Given: x= -2. \\ \\ </p><p>x \div 2 + x - 2 = kx - 1x÷2+x−2=kx−1 \\ \\ </p><p>- 2 \div 2 + ( - 2) - 2 = k( - 2) - 1−2÷2+(−2)−2=k(−2)−1 \\ \\ </p><p>- 1 - 4 = k( - 2)- 1−1−4=k(−2)−1 \\ \\ </p><p>- 1 + 1 - 4 = - 2k−1+1−4=−2k \\ \\ </p><p>4 = 2k4=2k \\ \\ </p><p>k = 2.k=2.$