Question

8. Find the value of the following expressions at x = -2, y 3: (ii) (x + y)² - 2xy - x²y + x²y.



solve and explain ​

Answer 1

Answer:

put the value of X and Y in given equation

(-2+3) ^2 -2*(-2*3) -(-2*-2*3) +(-2*-2*3)

1+12-12+12

13

Answer is 13

Answer 2

Step-by-step explanation:

x= -2;

y= 3;

f(x) = (x + y)² - 2xy - x²y + x²y.

f(-2, 3) = (-2 + 3)² - 2(-2) (3)- (-2)²3 + (-2)²3

= (1)² +12 - 12 + 12

= 1+12

= 13

the value of polynomial at x= -2, y= 3 = 13