Question

8. Find the value of x in given figure, for which PQ || RS.
Р
R
x + 3
X-1
X + 1
X - 3
•T T
S​

Answer 1

Step-by-step explanation:

If PQ || RS => ∆POQ ~ ∆ROS

=> 1(x+5) = x−213x−31

=> 13x - 31 = (x-2)(x+5)

=> 13x – 31 = x2 – 2x + 5x – 10

=> 13x – 31 = x2 + 3x – 10

=> x2 – 10x +21 = 0

=> x2 – 7x – 3x +21 = 0

=> x(x-7) -3(x-7) = 0

=> (x-3)(x-7) = 0

=> x = 3, 7