Question

8. Find the values of y for which the distance between the points P(2. - 3) and Q(10, y) is
10 units.​

Answer 1

Step-by-step explanation:

pq^2=(10-2)^2+(y+3)^2

10^2=(8)^2+(y+3)^2

100=64+(y+3)^2

100-64=y+3^2

36=y+3^2

taking square root

6=y+3

y=3