Question

8. Find the values of y for which the distance between the points P(2, -3) and Q(10,y) is
10 units​

Answer 1

in this we are using distance formula in which we have to find the difference of xs and us

Answer 2

Given:

P(2, -3) =(x1, y1)

Q(10, y) =(x2,y2)

To Find:

y=?

Solution:

d(P, Q) =√(y2-y1) ²+(x2-x1) ²...... (Formula)

d(P, Q) =√(y+3) ²+(10-2) ²

d(P, Q) =√(y+3) ²+8²

d(P, Q) =√y²+6y+9+8²

d(P, Q) =√y²+6y+9+64

d(P, Q) =√y²+6y+73

10=√y²+6y+73

10²=y²+6y+73

100=y²+6y+73

100-73=y²+6y

27=y²+6y

y²+6y-27=0..... (Quadratic equation)

y²+9y-3y-27=0

y(y+9) -3(y+9) =0

(y-3) (y+9) =0

y-3=0 or y+9=0

y=3 or y=-9