Question

8. Find the values of y for which the distance between the points P(2-3) and Q(10. y) is
10 units​

Answer 1

Answer:

y = - 9

Step-by-step explanation:

d = $\sqrt{(x_{2} -x_{1} )^2 + (y_{2} -y_{1} )^2}$

P (2, - 3) , Q (10, y) and d = 10

10² = (2 - 10)² + (- 3 - y)²

(- 3 - y)² = 100 - 64

(- 3 - y)² = 36 = 6² ⇒ - 3 - y = 6 ⇒ y = - 9