Question

8.) Find the weight of a solid rectangular block of iron of size 50 cm by 40 cm by 10 cm, if 1 cm³ of
iron weighs 7.8 g.​

Answer 1

Answer:

The weight of the rectangular solid block is 156,000g.

Step-by-step explanation:

Given :-

Dimensions of the rectangular solid block are:

50cm,40cm and 10cm.

Formula used :

Volume of cuboid =l×b×h

To find :

The weight of the rectangular solid block =??

Solution :

$volume = l \times b \times h$

$volume = 50 \times 40 \times 10$

$volume = 20000 {cm}^{?}$

Now as,

1 cm ³ =7.8g

20,000cm³=20,000×7.8g

20,000cm³= 156,000g

Answer 2

Answer:

156kg

Step-by-step explanation:

Answer:

The weight of the rectangular solid block is 156,000g.

Step-by-step explanation:

Given :-

Dimensions of the rectangular solid block are:

50cm,40cm and 10cm.

Formula used :

Volume of cuboid =l×b×h

To find :

The weight of the rectangular solid block =??

Solution :

volume = l \times b \times hvolume=l×b×h

volume = 50 \times 40 \times 10volume=50×40×10

volume = 20000 {cm}^{?} volume=20000cm

?

Now as,

1 cm ³ =7.8g

20,000cm³=20,000×7.8g

20,000cm³= 156,000g