Question

8.) Find the zeroes of the quadratic polynomial
$x {}^{2} + 2x - 3$
Standard:- 10

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Answer 1

$\large {\mathbf {\red {Hello!!}}}$

$\blue {\bold {Here \: is \:the \: answer}}$

Given :
$x {}^{2} + 2x - 3$

By breaking the mid term....

We have to find two numbers such that their sum = 2 and product = -3.

By looking at the$\blue{prime \: factorisation}$ of 3, we get two numbers as -1 and 2.

So,
⏩ x^2 + 3x - 3 = 0
⏩ x^2 + 3x - x - 3 = 0
⏩ x (x + 3) - 1 ( x + 3) = 0
⏩ (x + 3)(x - 1) = 0

By comparing with zero...
x + 3 = 0 and x-1 = 0
x = -3 and x = 1.

$\large {\mathbf {\red {HOPE \: \: IT \:\: HELPS !!}}}$

Answer 2

HEY BUDDY...!!!

HERE'S THE ANSWER...

________________________

Q :- Find the zeroes of x^2 + 2 x - 3 = 0

=> x^2 + 2 x - 3 = 0

▶️ Now splitting the middle terms

=> x^2 - x + 3x - 3 = 0

▶️ taking common

=> x ( x - 1 ) + 3 ( x - 1 ) = 0

=> ( x + 3 ) ( x - 1 ) = 0

Now

#1 > x + 3 = 0

=> x = - 3

#2 > x - 1 = 0

=> x = 1

⏺️ So the zeroes of the polynomial are - 3 and 1

HOPE HELPED..

HAVE A NICE DAY..

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