8. Find the zeros of the quadratic polynomial (8x² - 4) and verify the
relation between the zeros and the coefficients.
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Answer:
Answer
Let f(x)=8x
2
−4
= 4((
2
x)
2
−(1)
2
)
=4(
2
x+1)(
2
x−1)
to find the zeroes, Let f(x)=0
(
2
x+1)(
2
x−1)=0
(√2x+1)=0 or (√2x−1)=0
x=
2
(−1)
or x=
2
1
So the zeroes of f(x) are
2
−1
and x=
2
1
Again
Sum of zeroes =
2
−1
+
2
1
=
2
(−1+1)
=0=
a
−b
=
(coefficient of x
2
)
(−coefficient of x)
Product of zeroes =
2
−1
×
2
1
=
2
−1
=
8
−4
=
a
c
=
coefficient of x
2
Constant term
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