8.
For a inductor coil L=0.04 H, then workdone by source
to establish a current of 5A in it is :-
(AIPMT 1999)
(1) 0.5 J (2) 1.00 J (3) 100 J (4) 20 J
Answers
Answer:
the work done is 0.5 J
Explanation:
Work done = 1/2 L I^2
Work done by source to establish current of 5A in inductor coil of 0.04 H is 0.5 J. Correct answer is option (1).
We know that work done energy is the capacity of a body to do work so work done by any body is stored in the form of energy.
Similarly work done in the coil is stored in the form of energy in the inductor coil. Energy in the coil is in form of magnetic field. So we have energy of inductor coil as 1/2*L*i^2 where we have;-
L is the inductance of the coil = 0.04 H
i is the current induced in coil due to magnetic field so i = 5A
Work done = energy =1/2Li^2
Substituting values we have:-
Work done = 1/2*0.04*(5)^2
Work = 25*0.02 = 0.5 Joules.
Hence work done by source to establish current of 5A in inductor coil of 0.04 H is 0.5 J.