Question

8. For an A.P. if S10 = 150 and S9= 126, find t10-
[Note: t10 = S10-S9)​

Answer 1

Answer:

It is 24

Step-by-step explanation:

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Answer 2

Answer:

24

Step-by-step explanation:

Let the first be a and common difference is d .

According to the question '

S₁₀ = 150 = (10/2) (2a + 9d)

2a + 9d = 30           ( equation 1)

S₉ = 126 = (9/2) ( 2a + 8d)

2a + 8d = 28        ( eqation 2 )

substract equation 2 from equation 1 , we get

a = 6 & d = 2

t₁₀ = a + 9d  = 6 + 9 *2 = 6 + 18 = 24