Question

8. For any positive integer n, prove that n'3-n is divisible by 6.​

Answer 1

Since, n (n – 1) (n + 1) is divisible by 2 and 3. Therefore, as per the divisibility rule of 6, the given number is divisible by six. n3 – n = n (n – 1) (n + 1) is divisible by 6.

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