Question

8. For each of two successive years, bean pricesrose by 10%. At the beginning of the firstyear, 1 kg of bean cost $20. At the end of thesecond year, how many grams of bean, to thenearest ten grams could be bought for $50?​

Answer 1

Step-by-step explanation:

▪️The end of one year, the price of 1kg of beans is (1+10%)(20)

▪️= 1.10*20 = 22

▪️At the end of year 2, the price of 1kg o= 1.10*22 = 24.2

▪️So we can purchase 1KG of beans for $24.20.

▪️Solving for KG/dollar 1KG/24.20 = (1/24.2)KG/dollar

▪️$50(1/24.2)= 2.066116KG = 2.0661 gram

▪️ beans is (1+10%)(22)

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Answer 2

Answer

• At the end of one year, the price of 1kg of beans is (1+10%)(20)= 1.10*20 = 22
• at the end of year 2, the price of 1kg of beans is (1+10%)(22)= 1.10*22 = 24.2
• So we can purchase 1KG of beans for $24.20.
• Solving for KG/dollar 1KG/24.20 = (1/24.2)KG/Dollar$50(1/24.2)= 2.066116KG = 2.0661 grams