Question

8. Form a quadratic equation whose roots are -3 and 4.​

Answer 1

Answer:

Step-by-step explanation:

(x-5)(x-2) = (x^2-2x-5x+10)

= x^2 -7x +10

which is the required equation

plz replace 5 by -3 and 2 by 4 as ur question gave different digits....

Answer 2

Formula to find quadratic equation when roots are given:

$\blue{\boxed{ {x}^{2} - ( \alpha + \beta ) x+ \alpha \beta = 0}}$

Where,

$\tt \alpha \: \: \: and \: \: \: \beta \: are \: roots$

${x}^{2} - ( - 3 + 4)x + ( - 3)(4) = 0$

$\orange{ \therefore { x}^{2} - x - 12 = 0}$

HOPE THIS HELPS!!