8 friends a, b, c, d, e, f, g & h are to be seated around a round table. Find the probability that a & b never sit next to each other
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Answer:
THE TOTAL NUMBER FRIENDS OF WAY= 8 - 1 = 7
THEREFORE TOTAL NUMBER OF WAY = 6
AGAIN THE SUCH A and B NEVER SIT TOGETHER = 7 -6 = 6 (7-1) = 6*6
THEREFORE THE NUMBER OF FAVOUR ABLE EVENT= 6*6
THUS THE EQUAL PROBABILITY =6*6/7
ANS IS 6/7..
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