Math, asked by deepuseth7250, 11 months ago

8 friends a, b, c, d, e, f, g & h are to be seated around a round table. Find the probability that a & b never sit next to each other

Answers

Answered by RvChaudharY50
1

Answer:

THE TOTAL NUMBER FRIENDS OF WAY= 8 - 1 = 7

THEREFORE TOTAL NUMBER OF WAY = 6

AGAIN THE SUCH A and B NEVER SIT TOGETHER = 7 -6 = 6 (7-1) = 6*6

THEREFORE THE NUMBER OF FAVOUR ABLE EVENT= 6*6

THUS THE EQUAL PROBABILITY =6*6/7

ANS IS 6/7..

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