Question

8. From QUESTION 7, find the VERTICAL component *

7. A 30N force acting at an angle 60 Degree to the horizontal. Find the value of Horizontal Component *

11. A boy pulls his friend sitting on trolley by means of rope inclined at 30 Degree to the Horizontal. if the tension T in the rope is 350N, calculate the effective force in pulling *

9. Man pulling a bag of sugar with a means of rope inclined at angle 60 Degree to the Horizontal. If the tension in the rope is 100N, find the effective force pulling the bag *

6. From QUESTION 5, find the VERTICAL COMPONENT of the force *

2. Two forces 20N and 40N acting on a body at opposite direction. what is the resultant force. *

3. Two forces 16N and 4N acts at right angle to each other. calculate the resultant force. LEAVE your answers in 3 sf

14. from QUESTION 13, what is its Vertical component *

13. if the resultant force of two forces at right angle is 10N, and it makes an angle of 60 Degree to the vertical, what is its Horizontal Component *

1. Two forces 8N and 10N acting in the same direction on a body. calculate the resultant force. *
5. A 20N force acting at an angle 30 Degree to the horizontal. Find its HORIZONTAL component. Leave your answers in 2dp *

12. from QUESTION 11, find the force tending to lift the trolley off the ground *

Determine the resultant force of the forces in the DIAGRAM ABOVE. LEAVE your ANSWER IN 3 SIGNIFICANT FIGURE *

10. from QUESTION 9, find the force tending to lift the sugar up *

Determine the direction of the forces in the DIAGRAM ABOVE. LEAVE your ANSWER IN 3 SIGNIFICANT FIGURE *


4. if the resultant force of two forces is 5N and one of the forces has a magnitude of 3N, what is the magnitude of the other force? *

Answer 1

Answer:

Explanation:

7.Horizontal component f(x)=f*cos(theta)

Vertical component f(y)= f*sin(theta)

Since your question say that horizontal component of 60N is 30N then theta must be pi/3 (60 deg) i.e

30=60*cos(theta)

theta=Cos inverse (30/60)

theta = 60 deg

Now vertical component f(y)=f*sin(theta)

So f(y)=60*sin(60)