8 g NaOH and 4.9 g H2SO4 are present in one
litre of the solution. What is its pH ,
Answers
Answered by
0
Explanation:
8gm of NaOH+H
2
SO
4
→NaHSO
4
+H
2
O
Mole =
40
8
M=
9.8
4.9
So now 0.1 mole of NaOH is left.
NaOH is the strong base so it dissociates completely into
ion OH
0
This results in 0.1 moles of (−)
+
ion PoH=−log[0.1]
PH=14−1
=138gm of NaOH+H
2
SO
4
→NaHSO
4
+H
2
O
Mole =
40
8
M=
9.8
4.9
So now 0.1 mole of NaOH is left.
NaOH is the strong base so it dissociates completely into
ion OH
0
This results in 0.1 moles of (−)
+
ion PoH=−log[0.1]
PH=14−1
=13
3
Similar questions