Question

8 g NaOH and 4.9 g H2SO4 are present in one
litre of the solution. What is its pH ,
​

Answer 1

Explanation:

8gm of NaOH+H

2

SO

4

→NaHSO

4

+H

2

O

Mole =

40

8

M=

9.8

4.9

So now 0.1 mole of NaOH is left.

NaOH is the strong base so it dissociates completely into

ion OH

0

This results in 0.1 moles of (−)

+

ion PoH=−log[0.1]

PH=14−1

=138gm of NaOH+H

2

SO

4

→NaHSO

4

+H

2

O

Mole =

40

8

M=

9.8

4.9

So now 0.1 mole of NaOH is left.

NaOH is the strong base so it dissociates completely into

ion OH

0

This results in 0.1 moles of (−)

+

ion PoH=−log[0.1]

PH=14−1

=13

3