Question

8 g naoh is dissolved in 450 ml solution. The molarity of solution is?

Answer 1

Answer : The molarity of solution is, 0.44 mole/L

Solution : Given,

Mass of NaOH (solute) = 8 g

Molar mass of NaOH (solute) = 40 g/mole

Volume of solution = 450 ml

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution in ml}}$

Now put all the given values in this formula, we get the molarity of the solution.

$Molarity=\frac{8g\times 1000}{40g/mole\times 450ml}=0.44mole/L$

Therefore, the molarity of solution is, 0.44 mole/L

Answer 2

Answer:

Explanation:

The molarity of solution is, 0.44 mole/L

Solution : Given,

Mass of NaOH (solute) = 8 g

Molar mass of NaOH (solute) = 40 g/mole

Volume of solution = 450 ml

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

Now put all the given values in this formula, we get the molarity of the solution.