8 g naoh is dissolved in one litre of solution its molarity is
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Molarity of a solution is defined as the number of moles of solute dissolve in unit Volume of solution ( 1 Litre of Solution...
Here Solute is NaOH...
Molar Mass of NaOH = 23 + 16 + 1 = 40g
Moles of NaOH in 8g
= (8g of NaOH) x [ 1 Mole of NaOH / 40g of NaOH ]
= 8 x 1 / 40
= 1 / 5 = 0.2
Volume of Solution = 1 L
Molarity = No. of Moles of NaOH / Volume of solution
= 0.2 / 1
= 0.2 M
Here Solute is NaOH...
Molar Mass of NaOH = 23 + 16 + 1 = 40g
Moles of NaOH in 8g
= (8g of NaOH) x [ 1 Mole of NaOH / 40g of NaOH ]
= 8 x 1 / 40
= 1 / 5 = 0.2
Volume of Solution = 1 L
Molarity = No. of Moles of NaOH / Volume of solution
= 0.2 / 1
= 0.2 M
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