8 girls and 12 biys can finish a work in 10 days while 6 girls and 8 boys can finish it in 14 days. Find the time taken by 1 girl alone and 1 boy alone to finish the work
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take boys as=y
girls as=x
so,8x+12y=10
6x+8y==14
take LCM of 8and 6
3(8x+12y)=(10)3
4(6x+8y)=(14)4
subtract the equations
24x+36y=30
24x+32y=56
4y= -26
y= 26\4
y= 6.5
so,one boy can do it in 6.5 days
8x+12y=10
8x+12(6.5)=10 ...... y= 6.5
8x+78=10
8x=78-10
8x=68
x=8.5
so ,one boy can do it in 6.5 and girl can do it in 8.5
girls as=x
so,8x+12y=10
6x+8y==14
take LCM of 8and 6
3(8x+12y)=(10)3
4(6x+8y)=(14)4
subtract the equations
24x+36y=30
24x+32y=56
4y= -26
y= 26\4
y= 6.5
so,one boy can do it in 6.5 days
8x+12y=10
8x+12(6.5)=10 ...... y= 6.5
8x+78=10
8x=78-10
8x=68
x=8.5
so ,one boy can do it in 6.5 and girl can do it in 8.5
Cheenubird1234:
Thanks mate! But I have four options:
a)120,130
b) 140,280
c) 240,280
d) 100,120
Which one of these is the answer?
i think a or d
any one man can this much time he may take as i gave the answer
Thx mate!
tq to you my friend
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