Question

8 girls and 12 boys can fiish the work in 10 days while 6 girls and 8 boys can finish it in 14 days.find the time taken by one girl alone and then one boy alone to finish the work.​

Answer 1

Step-by-step explanation:

Let x and y represent work done per day by boy and girl respectively:

8x + 12y = 1/10    

6x  + 8y = 1/14    |multiplying thru by -3/2 to  eliminate the y variable

8x + 12y = 1/10    

-9x  -12y = -3/28    |result of multiplying thru by -3/2 to  eliminate the y variable

x = 1/140  and y = 1/280, work PER Day by each

time taken by 1 boy alone140 days and 1 girl alone 280 days to finish the work.

I hope this answer is helpful for you.

Answer 2

Answer:

Let the time taken by girl  be 'x' days

time taken by boys be 'y' days

So A/c to given conditions,

8x+12y=1/10 ...(1)[for 1 day]

6x+8y=1/14...(2)[for 1 day]

Now 2*(1)-3*(2),we get ,

(16x+24y)-(18x+24y)=1/5-3/14

=> -2x = -1/70

=> x = 1/140

sub. this value in (1) , we get ,

8 (1/140)+12y=1/10

=>y = 1/280

So , A girl complete the work in 140 days

and A boy can complete the work in 280 days

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