Math, asked by pravatkumarparida612, 6 months ago


8) Given that sin a =1/2 and cos b=1/2,find the value of cosec(a+b)​

Answers

Answered by bhatbhargavi06
2

Answer:

1

Step-by-step explanation:

sin A =1/2, cos B= 1/2

sin A = cos B

sin A= sin (90-B)

Therefore, A= 90-B

A+B = 90

cosec(A+B)= cosec 90

cosec 90= 1

Hope it helps. Please mark as brainliest.

Answered by 11a31JoanneTom
1

Answer:

1

Step-by-step explanation:

sin a=1/2

∴a=30°

cos b=1/2

∴b=60°

cosec(a+b)= cosec(30+60)

                 =cosec 90

∴cosec(a+b)=1/sin 90 (cosec=1/sin)

                   =1/1 = 1

Similar questions