8) Given that sin a =1/2 and cos b=1/2,find the value of cosec(a+b)
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Answered by
2
Answer:
1
Step-by-step explanation:
sin A =1/2, cos B= 1/2
sin A = cos B
sin A= sin (90-B)
Therefore, A= 90-B
A+B = 90
cosec(A+B)= cosec 90
cosec 90= 1
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Answered by
1
Answer:
1
Step-by-step explanation:
sin a=1/2
∴a=30°
cos b=1/2
∴b=60°
cosec(a+b)= cosec(30+60)
=cosec 90
∴cosec(a+b)=1/sin 90 (cosec=1/sin)
=1/1 = 1
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