Question

8 gram 0² _ molecules of o² ?

Answer 1

Answer:

>> 1 g contains > 0.188 × 1023 molecules of di-oxygen.

∴ 8 g contains > 0.188 × 8 × 1023 molecules of di-oxygen.

Step-by-step explanation:

Answer 2

Answer:

approximately 1.51×10^23

Step-by-step explanation:

no. of molecules/Na=weight/molecular weight

Therefore,

P/Na=8/32

P=1/4×6.023×10^23

P=1.51×10^23

(I have substituted no. of molecules to P)