8 gram complete burning of CH4 gives 18 gram of Co2 the percentage of yield is
a . 99.2%
b . 99.5%
c. 81.81%
d. 90.90%
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Answer:
c.81.81%
Explanation:
Gram molecular mass(GMM) of CO2=44g
GMM of CH4 =16g
16g of CH4 should give 44g of CO2
8g of CH4 should give =(44/16)x8 g of CO2
=22g of CO2
%yield =(actual/theoretical)x100
=(18/22)x100
=81.81%
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