8 grams of Sulphur dioxide diffuses in 10 seconds weight of CH4 diffuse at the same time is
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given,
R1 ( sulphur dioxide) = 10,
R2 ( methane)= 10
M1 ( sulphur dioxide ) = 8g
let M2 ( methane ) be x
we know that,
R1/R2 = √M2/√M1
=> 10/10 = √x/√8
=> 1 = √x/√8
squaring in both sides
=>1=x/8
=>x=8g
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R1 ( sulphur dioxide) = 10,
R2 ( methane)= 10
M1 ( sulphur dioxide ) = 8g
let M2 ( methane ) be x
we know that,
R1/R2 = √M2/√M1
=> 10/10 = √x/√8
=> 1 = √x/√8
squaring in both sides
=>1=x/8
=>x=8g
HOPE U UNDERSTAND
PLS MARK IT AS BRAINLIEST
nikki1231:
pls mark it as BRAINLIEST
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