Question

8 grams of Sulphur dioxide diffuses in 10 seconds weight of CH4 diffuse at the same time is

Answer 1

given,

R1 ( sulphur dioxide) = 10,

R2 ( methane)= 10

M1 ( sulphur dioxide ) = 8g

let M2 ( methane ) be x

we know that,

R1/R2 = √M2/√M1

=> 10/10 = √x/√8

=> 1 = √x/√8

squaring in both sides

=>1=x/8

=>x=8g

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