Question

8. Half of a herd of deer are grazing in the field and three
fourths of the remaining are playing nearby. The rest 9
are drinking water from the pond. Find the number of
deer in the herd.
Arandfatherin
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Answer 1

★Given:-

• Half of a herd of deer are grazing in the field.
• Three  fourths of the remaining are playing nearby.
• The rest 9  are drinking water from the pond.

★To find:-

• Find the number of  deer in the herd.

★Solution:-

Let,

• Total no.of deer in the herd = x

Then,

• Half of herd of deer = x/2

3/4 of remaining half herds playing nearby:-

⇒(x/2)(3/4)

⇒3x/8

Given,Remaining no.of deer's = 9

According to question,

Total no of deer in the herd will be half of herd of deer added to three fourths of remaining deer playing nearby & the rest 9 which are drinking water.

That is,

⇒x=(x/2)+(3x/8)+9

⇒x=(4x+3x+72)/8

⇒8x=7x+72

⇒8x-7x=72

⇒x=72

Therefore,total no.of deer's in the herd are 72.

_______________

Answer 2

Answer:

Question:-

1. Half of a herd of deer are gazing in field and three fourths of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.

To find,

• The number of deer in the herd

Given:-

• 3\4 deer are playing nearby
• 9 deer are drinking water

Let,

• No of deer in the herd be x

Required answer:-

• 72

Solution:-

✔ $\rm \frac{x}{2}$ deer are grazing

✔ Remaining = $\rm \frac{3}{4} (\frac{x}{2})=playing$

✔ $\rm\frac{3x}{8}$ are playing

✔ Remaining = $\rm \frac{1}{4}(\frac{x}{2})=9=$ drinking water

✔ $\rm \frac{x}{8}=9$

✔ x = $\rm 9 \times 8$

Answer = ✔ x = 72