Question

8.
How many halogen will be removed in the following E2 reaction?
C1
CI-
C1
ele KOH
→ Product
СІ
СІ
СІ
1) 0
2)3
3)4
4) 6​

Answer 1

Reaction is not given and question is not clear.

Basically one halogen is removed in an elimination reaction.

Explanation:

When an alkyl halide is treated with alcoholic KOH, Oh act as Halide ion is removed by KOH , and potassium halide and a water molecule is eliminted, while an alkene is formed. Alkenes are formed according to the seytzeff rule. Hydrogen is taken and bond is shifted as double bond in alkene. This is a beta elimination reaction because Hydrogen is removed from the carbon atom next to the carbon atom to which halogen is attached, which is called a beta carbon.

Answer 2

one halogen is removed in an elimination reaction.

Explanation:

1.elimination reaction, any of a class of organic chemical reactions in which a pair of atoms or groups of atoms are removed from a molecule, usually through the action of acids, bases, or metals and, in some cases, by heating to a high temperature.

2.Rate = k[RX][Base]

3. To identify an elimination reaction  we have to find the location of the leaving group, and note whether it is located on a primary, secondary, or tertiary carbon on the substrate.

4.If the leaving group is primary, then the reaction will typically be either E2 or SN2. If the leaving group is secondary, the reaction will tend to be E2 or SN2.