8. How many ions of each kind are present in 66.75 g of aluminum chloride
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0
Answer:
Moles of aluminum chloride = approx. 0.250 moles
Explanation:
Moles=
Molarmassofcompounds
Massofcompounds
=
(26.98+3×35.45).g.mol
−1
32.5.g
=
133.33.g.mol
−1
32.5.g
=0.2437 moles
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Answer:
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