8−i/3−2i
If the expression above is rewritten in the form a+bi, where a and b are real numbers, what is the value of a? (Note: i=√−1)
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Step-by-step explanation:
So you are asking for Re(8−i3−2i)
First problem is, we haven’t got something which looks like a+bi here, so we have to simplify (8-i)/(3–2i).
Multiply numerator and denominator by the conjugate of the latter:
8−i3−2i=(8−i)(3+2i)13
Simplify:
=26+13i13=2+i
So Re(8−i3−2i)=Re(2+i)= 2
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