Physics, asked by prajaktahanamgaon, 5 months ago

8) i.j is equal to :
A) zero
B) one
C) square of magnitude
D) null vector​

Answers

Answered by parimeshram040
0

Explanation:

(a) In order to make vectors a + b + c + d = 0, it is not necessary to have all the four given vectors to be null vectors. There are many other combinations which can give the sum zero.

(b) Correct

a + b + c + d = 0

a + c = -(b + d)

Taking modulus on both the sides, we get:

| a + c | = | -(b + d)| = | b + d |

Hence, the magnitude of (a + c) is the same as the magnitude of (b + d).

(c) Correct

a + b + c + d = 0

a = - (b + c + d)

Taking modulus both sides, we get:

| a | = | b + c + d |

| a | ≤ | b | + | c | + |d| .... (i)

Equation (i) shows that the magnitude of a is equal to or less than the sum of the magnitudes of b, c, and d.

Hence, the magnitude of vector a can never be greater than the sum of the magnitudes of b, c, and d.

(d) Correct

For a + b + c + d = 0

a + (b + c) + d = 0

The resultant sum of the three vectors a, (b + c), and d can be zero only if (b + c) lie in a plane containing a and d, assuming that these three vectors are represented by the three sides of a triangle.

If a and d are collinear, then it implies that the vector (b + c) is in the line of a and d. This implication holds, only then the vector sum of all the vectors will be zero.

Answered by sayyedmohammadali12
0

Answer:

B)one

Explanation:

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