Question

8. If 2 is a root of kx^2+2x-1=0 then value of k is *​

Answer 1

$k {x}^{2} + 2x - 1 = 0 \\ k {(2)}^{2} + 2(2) - 1 = 0 \\ 4k + 4 - 1 = 0 \\ 4k + 3 = 0 \\ 4k = - 3 \\ k = \frac{ - 3}{4}$

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Answer 2

Answer:

k = -3/4

Step-by-step explanation:

4k + 4 - 1 = 0

4k = -3

k = -3/4