Question

8. If 2x, X+10, 3x+2 are in AP, find the value of x.
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Answer 1

Given 2x, x + 10 and 3x + 2 are in AP

Hence their common difference would be same

( 3x + 2 ) – ( x + 10 ) = ( x + 10 ) – 2x

3x – x + 2 – 10 = x – 2x + 10

2x – 8 = –x + 10

2x + x = 10 + 8

3x = 18

x = 18/3

x = 6

Answer 2

Answer:

GIVEN,

A.P--> 2x, x+10, 3x+2

d= a2-a1=a3-a2

a1=2x

a2=x+10

a3=3x+2

$(x + 10) - 2x = (3x + 2) - (x + 10) \\ x + 10 - 2x = 3x + 2 - x - 10 \\ 10 - x = 2x - 8 \\ 10 + 8 = 2x + x \\ 3x = 18 \\ x = \frac{18}{3} \\ x = 6$

Step-by-step explanation:

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