Question

8. If 30 g of NOx, (g) occupies 22.4 L at STP then the
value of x is
(1) 2.
(2) 1
(3) 0.5
(4) 2.5​

Answer 1

Answer:

We know that at S.T.P, 1 mole of each ideal gas occupies the volume of 22.4 lit. So that,5.6 lit gas is occupied by 5.6/22.4 =0.25 mole. On the other hand 0.25 mole=16g,so 1 mole=16/0.25=64g. As we know the whole atomic mass of SOx=1 mole SOx=64,so 32+16x=64,or,x=2. HOPE IT HELPS.