Question

8 If a + b + c = 0, show that : a3 + b3 + c3 = 3abc.​

Answer 1

Answer:

We know,

a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)

Putting a+b+c=0 on RHS, we get,

a3+b3+c3−3abc=0

⟹a3+b3+c3=3abc, Hence proved.

Step-by-step explanation:

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